How to return the node with most relationships

General Newbie Questions
1

Hi,

Based on my example below, i wanted to return list of user stories (US1 and US2) ordered by the number of tickets related to it that is also linked SP1. In other words, find me userstories (starting) with greatest number of tickets linked to SP1.

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this is query I've got right now:

MATCH (:Sprint{id:"SP1"})<-[:SPRINT_TASK]-(:Ticket)-[:SUB_TASK]->(rec:UserStory)
WITH rec, COUNT(*) AS num ORDER BY num DESC 
RETURN rec

Any help will is greatly appreciated :)

2 
MATCH (:Sprint{id:"SP1"})<-[:SPRINT_TASK]-(:Ticket)-[:SUB_TASK]->(rec:UserStory)
WITH rec, COUNT(*) AS num ORDER BY num DESC
RETURN rec, num

This will return two nodes US1 and US2 . If you click "Table" button on the left side of the output, you will get what you want.

If you don't like this, try below

If you have declared your node as (:UserStory{ name : "US1" }) ,try

MATCH (:Sprint{id:"SP1"})<-[:SPRINT_TASK]-(:Ticket)-[:SUB_TASK]->(rec:UserStory)
WITH rec, COUNT(*) AS num ORDER BY num DESC 
RETURN rec.name,num

Hope this helps you.

1 Like
3

Try this

MATCH (:Sprint{id:"SP1"})<-[:SPRINT_TASK]-(:Ticket)-[r1:SUB_TASK]->(rec:UserStory)
WITH rec, COUNT(r1) AS num ORDER BY num DESC
RETURN rec,num

1 Like