Cypher Statement Not giving Desired Result in Neo4j?

Neo4j Graph Platform Cypher
,
1

Hello All I'm new to Neo4j, I'm trying to learn Neo4j. This example I have chosen is process of resolving issue related to Mobile repair.

Below shown are 3 columns for Operation1&2 (which are done by Operator ID A,B,C..etc) and Time for both operations to complete for particular mobile issue to be resolved
(OPER_1,OPER_2,Time)
(A, A, 6)
(A, A, 8)
(A, B, 3)
(B, C, 4 )
(C, D, 6)
(D, E, 9)

I wanted to create a graph with nodes as Operator & time on relations as shown below:

A---6-->A---8--->A---3--->B---4--->C----6--->D---9--->E

I have used below query:

LOAD CSV WITH HEADERS FROM "file:///C:/xyz.csv" AS line
CREATE (n:Oper1 {,OperId:line.OPER_1})
CREATE (m:Oper2 {OperId:line.OPER_2})
WITH n,m
CREATE (n) -[:TO {TimeUsed: line.Time} ]-> (m)

But it creating something like this:
A--6--->A, A---8--->A,A--3--->B, B--4--->C, C---6--->D, D---9--->E all relations are separately generated.

What should I do?

2

it appears your result created 6 pairs where each node points to another node but what you wanted was one long path? is that correct?
If so change the CREATE to a MERGE and retry.
And so with Neo4j 4.2.5 and with a csv defined as

OPER_1,OPER_2,Time
A,A,6
A,A,8
A,B,3
B,C,4
C,D,6
D,E,9

note I removed the leading ( and trailing ) from each line

And when running

LOAD CSV WITH HEADERS FROM "file:///test.csv" AS line
MERGE (n:Oper {OperId:line.OPER_1})
MERGE (m:Oper {OperId:line.OPER_2})
MERGE (n) -[:TO {TimeUsed: line.Time} ]-> (m);

the result is

result
result1419×456 27.1 KB

1 Like
3

Thank you @dana_canzano for the idea.

Yes, for me the result created 6 pairs where each node points to another node. But is it possible to create one long path without the loops at A ??

4

The first two rows of your .csv file has:

OPER_1,OPER_2,Time
A,A,6
A,A,8

With this you cannot avoid the observed behavior.

1 Like
5

Okay, Thank you @ameyasoft

6

avoiding loops?

But your initial statement of

I wanted to create a graph with nodes as Operator & time on relations as shown below:
A---6-->A---8--->A---3--->B---4--->C----6--->D---9--->E

demonstrates a loop of A---6-->A---8--->A ? no?

1 Like
7

Yes true @dana_canzano it forms a loop.

In the context of my application, I wanted to depict in graph the process of how mobile traversed for repair. I might have modeled it wrong. Thanks for the inputs, I have corrected it now.