Count the number of duplicates in result

Hello community,

I am new to neo4j and I'm trying to get a list of nodes (that has not a specific relation) and count node name duplicates.

Query:

MATCH (e:ExampleNode)
WHERE NOT exists((e)-[:EXAMPLE_REL]->())
RETURN e.name as name, count(e.name) as count

Result:

name count

name1

3

name23

1

name8

4

So far so good...

Beside the name of the node I also need some more values. This value makes each result unique and returns every node separately even (if the name is the same).

Query:

MATCH (e:ExampleNode)
WHERE NOT exists((e)-[:EXAMPLE_REL]->())
RETURN e.name as name, count(e.name) as count, e.property as someValue

Result:

name count someValue

name1

1

abc

name1

1

cba

name1

1

xyz

name23

1

abc

name8

1

123

name8

1

321

name8

1

987

name8

1

789

...

...

...

But...this is the result I would like to have:

name count someValue

name1

3

abc

name1

3

cba

name1

3

xyz

name23

1

abc

name8

4

123

name8

4

321

name8

4

987

name8

4

789

...

...

...

I would like to return every node that hasn't the specific relation and count all duplicates by the name.

So, is it possible to get the result I would like to have?

Hello @ovashape :slightly_smiling_face:

MATCH (e:ExampleNode)
WHERE NOT exists((e)-[:EXAMPLE_REL]->())
WITH e.name as name, count(e.name) AS count, collect(e.property) AS values
UNWIND values AS value
RETURN name, count, value

Regards,

Cobra

Thanks for your quick answer. This solved my problem.