# Return all paths from one node to another node **URL:** \ **Category:** Cypher\ **Created:** [January 6, 2021, 12:06am UTC](https://community.neo4j.com/t/return-all-paths-from-one-node-to-another-node/31570 "2021-01-06T00:06:50Z")\ **Posts on this page:** 3\ **Page:** 1
**Author:** ![fruitfulapproac](https://sea1.discourse-cdn.com/flex021/user_avatar/community.neo4j.com/fruitfulapproac/32/2627_2.png) [@fruitfulapproac](https://community.neo4j.com/u/fruitfulapproac)\ **Post date:** [January 6, 2021, 12:06am UTC](https://community.neo4j.com/t/return-all-paths-from-one-node-to-another-node/31570/1 "2021-01-06T00:06:50Z")
Was wondering how to do this in Cypher. In a commutative diagram these paths represent equal morphisms. This method is deprecated: `MATCH p=(a{LaTeX:"A"})-[r*]->(b{LaTeX:"C"}) RETURN p` ---
**Author:** ![tard\_gabriel](https://sea1.discourse-cdn.com/flex021/user_avatar/community.neo4j.com/tard_gabriel/32/28033_2.png) [@tard\_gabriel](https://community.neo4j.com/u/tard_gabriel)\ **Post date:** [January 6, 2021, 12:13am UTC](https://community.neo4j.com/t/return-all-paths-from-one-node-to-another-node/31570/2 "2021-01-06T00:13:30Z")
MATCH paths = (n1)-[\*]-(n2) RETURN paths SKIP x LIMIT 1 Replace x by 0, 1, 2, 3 for each path (query) you want to see on neo4j desktop. OR MATCH paths = (n1)-[\*]-(n2) RETURN paths Will return all your paths in the Table tab view. _But you will still see all your graph in the Graph tab view_ ---
**Author:** ![fruitfulapproac](https://sea1.discourse-cdn.com/flex021/user_avatar/community.neo4j.com/fruitfulapproac/32/2627_2.png) [@fruitfulapproac](https://community.neo4j.com/u/fruitfulapproac)\ **Post date:** [January 8, 2021, 4:20am UTC](https://community.neo4j.com/t/return-all-paths-from-one-node-to-another-node/31570/3 "2021-01-08T04:20:53Z")
You, son, are a gifted genius, thank you! 😃