# Having a label as a parameter in a cypher query (efficiently) **URL:** \ **Category:** Neo4j Graph Platform\ **Tags:** migrated\ **Created:** [October 3, 2020, 9:32pm UTC](https://community.neo4j.com/t/having-a-label-as-a-parameter-in-a-cypher-query-efficiently/59620 "2020-10-03T21:32:29Z")\ **Posts on this page:** 2\ **Page:** 1
**Author:** ![roymaor1](https://sea1.discourse-cdn.com/flex021/user_avatar/community.neo4j.com/roymaor1/32/4107_2.png) [@roymaor1](https://community.neo4j.com/u/roymaor1)\ **Post date:** [October 3, 2020, 9:32pm UTC](https://community.neo4j.com/t/having-a-label-as-a-parameter-in-a-cypher-query-efficiently/59620/1 "2020-10-03T21:32:29Z")
Hello all, I am looking for a way to get a label as a string from my user **AND** use the label optimization in my query (rather than have the engine go for a full DB scan). 2 ways I have found so far of doing so (I'll use the WITH keyword to simulate user input): 1. ```auto WITH "facebook" as company MATCH p = (a:company)-->(b:company) RETURN p ``` This one just won't work, as cypher apparently does not know how to handle form of (node\_name:label\_name) when label\_name is a parameter. ```auto WITH "facebook" as company MATCH p = (a)-->(b) WHERE ALL (x IN nodes(p) WHERE company IN labels(x)) RETURN p ``` This one works, but performs a full DB scan, not using the label optimization benefit for improved performance. Any ideas? Thanks! ---
**Author:** ![danielfrees](https://avatars.discourse-cdn.com/v4/letter/d/bcef8e/32.png) [@danielfrees](https://community.neo4j.com/u/danielfrees)\ **Post date:** [September 27, 2022, 7:54pm UTC](https://community.neo4j.com/t/having-a-label-as-a-parameter-in-a-cypher-query-efficiently/59620/2 "2022-09-27T19:54:57Z")
Nevermind on my original reply. Can't see how to delete this lol.